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using elimination!!

2x+5y=3
-x+3y=-7

2007-02-22 14:02:46 · 6 answers · asked by Anonymous in Science & Mathematics Mathematics

6 answers

2x + 5y = 3
2(-x + 3y)= 2(-7) { multiplying 2 both sides}

then by adding 2 equations we get,

11y = -11

y = -1

now put value of y in any of the above eqations,

2x + 5(-1)=3
2x-5=3
x=4
y=-1

hence solved!

2007-02-22 14:14:45 · answer #1 · answered by ur_max 2 · 0 1

Solve for x in one of the equations.

-x+3y=7
-x=7-3y
x=-7+3y

Now you know what x is equal to. So substitute x into the other equation.

2x + 5y =3
2(-7+3y) + 5y =3
-14 + 6y + 5y = 3
-14 + 11y =3
11y = 17
y= 17/11


Then put y back into one of the equations to figure out what x is equal to.

2x + 5y = 3
2x + 5(17/11) = 3
2x + 85/11 = 3
2x = 3 - 85/11
22x = 33 - 85
22x = -52
x = -52/22 or -26/11

so, y= 17/11 and x= -26/11

2007-02-22 14:10:11 · answer #2 · answered by Y-Knot 3 · 0 1

2x+5y=3
-x+3y=-7
3y+7=x

Then substitue x into the first equation to isolate y:
2(3y+7)+5y=3. Distribute:
6y+14+5y=3, which simplifies into:
11y+14=3

Now solve for y:
11y=-11
y=-1

Plug that back into an original equation:
3(-1)+7=x
x=4

The person posting above me should check his answer...

2007-02-22 14:11:28 · answer #3 · answered by Thirdeye 2 · 0 0

2x+5y=3
-x+3y=-7 (multiply by 2)

2x+5y= 3
-2x+6y=-14
----------------
11y=-11
y=-11\11 => y=-1

2x+5(-1)=3
2x-5=3
2x=3+5
x=8/2 => x=4

2007-02-22 14:21:27 · answer #4 · answered by Ivan 2 · 0 1

2x + 5y = 3 .......................................( 1)
-x + 3y = -7 .......................................( 2)

Multiply ( 2 ) x 2
-2x + 6y = -14 .......................................( 3)

Add ( 1 ) & ( 3 )
11 y = -11
y = -1

Substitute this result to ( 3 )
-2x +6 (-1) = -14
-2x - 6 = -14
-2x = -14 +6 = -8
2x = -8
x = -4.


Hence the ans. is x = -4 & y = -1

2007-02-22 16:46:31 · answer #5 · answered by brainy 4 · 0 1

HINT: multiply the bottom one by 2 (all elements!). Add the top/bottom, leaving you with a simply solve for y equation. Plug that value into either of the ORIGINAL ones and get x!

2007-02-22 14:09:55 · answer #6 · answered by Anonymous · 1 0

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