I have [a^2 x (a-b)] + [ab x (a-b)] + [b^2 x (a+b)]. How do i get that to
(a+b) x (a^2 - ab + b^2)?
2007-02-22 13:35:17 · 7 answers · asked by Kingdiv 2 in Science & Mathematics ➔ Mathematics
x is multiply
2007-02-22 13:43:22 · update #1
aa (a - b) + ab (a - b) + bb (a + b)
= (aa (a - b) + ab (a - b)) + bb (a + b)
= (aa+ab) (a - b) + bb (a + b)
= a(a + b) (a-b) + (a+b) bb
= (a+b) a (a-b) + (a+b) bb
= (a +b) (a(a-b) + bb)
= (a + b) (aa - ab + bb)
= (a+b) (a^2 - ab + b^2)
2007-02-22 13:46:57 · answer #1 · answered by J Dunphy 3 · 0⤊ 0⤋
a^2 x (a - b) + ab x (a - b) + b^2 x (a + b)
= a^3 - a^2 x b + a^2 x b - a x b^2 + a x b^2 + b^3 (Eq. 1)
= a^3 - a^2 x b + a x b^2 + a^2 x b - a x b^2 + b^3
= (a+b) x (a^2 - ab + b^2)
OR just note that Eq. 1 simplifies to a sum of cubes
2007-02-22 13:44:21 · answer #2 · answered by Anonymous · 0⤊ 0⤋
factor (a- b) out of 1st 2
(a-b)[a^2 + ab] + b^2(a+b)
(a-b)(a(a+b)) + b^2 (a+b)
[a+b] (a(a-b) +b^2)
(a+b) (a^2 -ab + b^2)
2007-02-22 13:42:01 · answer #3 · answered by richardwptljc 6 · 1⤊ 0⤋
yeah, like the previous poster said.
but if you simplify, i get a^3 +b ^3
2007-02-22 13:44:10 · answer #4 · answered by Anonymous · 0⤊ 0⤋
I just can't wait for Alg 2 Trig...SCREAMS!!
2007-02-22 13:39:01 · answer #5 · answered by fpsfreak101 2 · 0⤊ 0⤋
Is the "x" a variable or a multiplication sign?? Please tell me a variable.
2007-02-22 13:41:22 · answer #6 · answered by hacker_skillz 2 · 0⤊ 1⤋
you are on your own kid.
2007-02-22 13:37:46 · answer #7 · answered by Lizzie 5 · 0⤊ 0⤋