chemistry problem please do help me asap?

Question

For the ff. reactions, find the ff.
a. which of the reagents is the limiting reagent
b. what is the maximum amt. of each product that can be formed
c. how much of the other reagent is left over after the reaction is complete

1. consider the ff. reaction
3 NH4NO3 + Na3PO4 -> (NH4)PO4 + 3 NaNO3

Assuming that we started with 30 grams of ammonium nitrate and 50 grams of sodium phosphate.


and the other problem is 3 CaCO3 + 2 FePO4 -> Ca3(PO4)2 + Fe2(CO3)3

can anyone please help me! i so need help! i dont want to fail chemistry class =(

Answer 1

ok.

first change grams to moles. divide by the MM. 30g of NH4NO3 is .375mol(30/80). 50g of Na3PO4 is .305mol (50/164). Now to fing limiting factor, divide both moles by the coefficient. since .375/3 is less than .305,/1, NH4NO3 is the limiting factor.

Now, set up a chart. I always rewrite the equation:

3NH4NO3 + Na3PO4 --> (NH4)3PO4 + 3NaNO3

. 375 .305 0 0

-.375 -.125 +.125 +.375

0 .180 .125 .375


As i showed u, decrease the limiting factor down to zero. decrease the other one 1/3 as much(the coefficient of the one that went down to 0 was 3.) Now, obviously, the products start out at zero. They go up in the same proportions as the other ones went down.

The answers:

A) the limiting factor is the NH4NO3
B) the max amt of (NH4)3PO4 is .125mol.
"" '' '' '' NaNO3 is .375 mol.
C) the amount of the Na3PO4 is .180 mol.


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Answer 2

it is as person-friendly as Algebra can get. For the 1st question x+3=8 you in simple terms subtract the three from the two factors 3-3 and eight-3 and the respond would be x = 5. So provided that x = 5 then 5 + 3 = 8