Math help?

Question

I need this worked and explained so I can have an example to work from. Any help is greatly appreciated. Two examples:

Find the product

-6x2 ∙ 5x2





(4y + 3)(y2 + 3y + 1)

Answer 1

1)

-6x^2 (5x^2)

Remember that this follows the formula

(x^m) (y^n) = xy^(m+n)

So, this will equal -30x^4

(4y + 3)(y^2+3y+1)

First, multiply each term by 4y.

Second, multiply each term by 3.

Then, combine like terms:

(4y^3+12y^2+4y)+(3y^2+9y+3)

=4y^3+15y^2+13y+3

Regards,

Mysstere

Answer 2

you do mean (-6x^2 * 5x^2) right. ^2 means squared

first multiply the numbers,
then multiply the varibles. When you multiply numbers with exponets, you add the exponets

-6x^2 * 5x^2 = -30x^4


on the bottom problem, you have to multiple everything in the first (..) by everything in the 2nd (...), so rewrite it as

4y(y^2 + 3y + 1) + 3(y^2 + 3y +1)
4y^3 + 12y^2 + 4y + 3y^2 +9y + 3

now combine the like terms

4y^3 +15y^2 + 13y + 3

Answer 3

For the first problem all you need to do is multipy
(-6x2)(5x2)= -30x4 you multiply and then add the exponents.

For the second problem all you need to do is multipy by distribution and then combine like terms.
(4y+3)(2+3y+1)= you have to multiply every # by 4y(2y) 4y(3y) 4y(1)=8y+12y+4y and then multiply every # by 3(2) 3(3y) 3(1)you should get 8y+12y+4y+6+9y+3 then add like terms = 33y+9

Answer 4

a) -30x^4

b) Take the first term in the first factor and multiply it by each term in the second factor:

4y(y^2) + (4y)(3y) + (4y)(1) = 4y^3 + 12y^2 + 4y

Then do the same for the second term:

3(y^2) + 3(3y) + 3(1) = 3y^2 + 9y + 3

Add them and collect similar terms:

4y^3 + 12y^2 + 4y + 3y^2 + 9y + 3

= 4y^3 + (12y^2 + 3y^2) + (4y + 9y) + 3

= 4y^3 + 15y^2 + 13y + 3

Answer 5

-6*5*x*x*x*x = -30x^(2+2) = -30x^4

4y*y^2+4y*3y+4y*1+3*y^2+3*3y+3*1
4y^3 + 12y^2 + 4y + 3y^2 + 9y + 3
4y^3 + 15y^2 + 12y + 3

Answer 6

30x^4

4y^3+12y^2+4y+6y^2+9y+3 = 4y^3+10y^2+13y+3

Answer 7

-30x4




distribute the first two to each of the three in second parentheses and you get 4y3 + 12y2 + 4y + 3y2 + 9y
then reduce, 4y3 + 15y2 + 13y + 3