Geometry - Fatoring?

Question

Factor following (pls show steps)
x^3 + 8

FACTORING *****
a typo

Answer 1

x^3+8
=(x)x^3+(2)^3
=(x+2){9x)^2-x*2+(2)^2}
=(x+2)(x^2-2x+4)

Answer 2

To factor large polynomials (those greater than degree 2) we use polynomial long division

(this will be tough to show while writing in text, so bear with me)

find all factors of the constant number (8) that when you substitute the number into the expression it =s 0

(-2)^3 + 8 = 0

Therefore, x + 2 is a factor: now use long division


x+2 | x^3+0x^2+0x+8

The quotient is x^2 -2x +4 which will have to be factored using the quadratic formula

Therefore x^3 + 8 = (x+2)(x + a)(x+b)

(a and b are the roots of the quadratic formula)

Answer 3

Find the roots x^3=-8 x=-2

x^3+8=(x+2)*(x^2-2x+4) The second factor has no real roots

Answer 4

This is not geometry. This is high school algebra.

Go to the link below for a lesson on how to factor the DIFFERENCE OF CUBES.

Go to:

http://www.purplemath.com/modules/specfact.htm

Guido

Answer 5

this is simply x times x times x then add 8 or XxXxX+8.. Is there more to this problem?

Answer 6

(X + 2)(x^2 - 2x + 4)