HClO4 HOAc HCN HF
1x10^7 1.76x10^-5 4.93x10^-10 3.53x10^-4
which shows the conjugate bases listed by increasing strength?
A. ClO4-, F-, OAc-, CN-
B. CN-, F-, OAc-, ClO4-
C. CN-, OAc-, F-, CO4-
D. CN-, CLO4-, F-, OAc-
ClO4-, OAc-, CN-, F-
2007-02-22 11:36:00 · 3 answers · asked by galdon885 1 in Science & Mathematics ➔ Chemistry
According to the Ka values, the acids listed in decreasing strength would be
HClO4 > HF > HOAc > HCN
Kb=Kw/Ka so the strongest acid will have the weakest conjugate base:
ClO4- < F- < -OAc < CN-
so the answer is (A)
2007-02-23 00:46:23 · answer #1 · answered by bellerophon 6 · 1⤊ 0⤋
List Of Ka Values
2016-11-17 00:14:56 · answer #2 · answered by ? 4 · 0⤊ 0⤋
Ka = 4.0x10^-4 = [H+][NO2-] / [HNO2] start up with some assumptions: The conc. of NO2- is 0.50 M (from NaNO2); the contribution from the dissociation of HNO2 is small. The concentration of undissociated HNO2 is 0.sixteen M; the help via way of dissociation of HNO2 is small. 4.0x10^-4 = [H+] x 0.50 / 0.sixteen [H+] = a million.28x10^-4 pH = 3.89
2017-01-03 09:37:50 · answer #3 · answered by ? 4 · 0⤊ 0⤋