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If one could transport a simple pendulum of constant length from the Earth's surface to the Moon's, where the acceleration due to gravity is one-sixth (1/6) that on the Earth, by what factor would the pendulum frequency be changed?

a. about 6.0
b. about 2.5
c. about 0.41
d. about 0.17

2007-02-22 11:33:58 · 1 answers · asked by Tennis2127 2 in Science & Mathematics Physics

1 answers

Since the formula is √(g/L), the factor would be √6 or about 2.449

Note: This is the inverse of the multiplier for frequency, so the correct choice is actually c.

2007-02-22 11:45:19 · answer #1 · answered by Steve 7 · 0 0

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