A man lent $ 20,000 at a certain rate per cent, and $ 18,000 at 2% less. His annual income from both sources was $ 6,480. Find the rates.
2007-02-22 11:16:55 · 4 answers · asked by edison c d 4 in Science & Mathematics ➔ Mathematics
20,000R + 18,000(R-.02) = 6480
R(20,000 + 18,000) = 6480 + .02(18000)
R = [6480 + .02(18,000)]/(20000 + 18000)
R = .18
Therefore: 18 percent and 16 percent.
2007-02-22 11:32:15 · answer #1 · answered by jeffrcal 7 · 0⤊ 0⤋
Use:
$20000 X R + $18000 X R-2 = $6480.
Remember R is a rate or percentage.
solve for R and you have your answer.
2007-02-22 19:35:14 · answer #2 · answered by John R 2 · 0⤊ 0⤋
20.000x+18000(x-0.02) =6480
38.000x= 6840 x=6840/38.000=.18 = 18% and 16%
2007-02-22 19:35:14 · answer #3 · answered by santmann2002 7 · 0⤊ 0⤋
20000i+18000(i-.02)=6480
Solve for i
2007-02-22 19:22:26 · answer #4 · answered by Rob M 4 · 1⤊ 0⤋