2007-02-22 11:07:41 · 8 answers · asked by Bob F 1 in Science & Mathematics ➔ Mathematics
In real No. system No,
In complex No. system ther R
x^2 + 4 = x^2 -4 i^2 ( where i = sqrt(-1))
= ( x - 2i ) ( x + 2i )
and more !!!
2007-02-22 11:14:06 · answer #1 · answered by a_ebnlhaitham 6 · 1⤊ 0⤋
Depends on the domain that you are doing the problem in...
over the real numbers...no. over the complex plane it can be factored into (x+2i)(x-2i). where ...i.... is the square root of -1.
be careful though (x+2)(x-2)=x^2-4.
If you know what the quadratic equation is you can use it to factor quadratic polynomials, which x^2+4 is.
2007-02-22 19:22:47 · answer #2 · answered by Dan R 2 · 1⤊ 0⤋
x^2 + 4 is already in factored form.
Guido
2007-02-22 19:11:17 · answer #3 · answered by Anonymous · 1⤊ 0⤋
NO! There is no sum of two squares factoring pattern!
if it was x^2 MINUS 4
it would factor to (x+2)(x-2)
2007-02-22 19:14:40 · answer #4 · answered by dla68 4 · 1⤊ 0⤋
No, that's how far that will factor out.
2007-02-22 19:16:18 · answer #5 · answered by Anonymous · 0⤊ 0⤋
(x+2)(x-2)
2007-02-22 19:12:04 · answer #6 · answered by nbr8sgirl 2 · 0⤊ 2⤋
No in real numbers
2007-02-22 20:54:45 · answer #7 · answered by santmann2002 7 · 1⤊ 0⤋
no
2007-02-22 19:23:09 · answer #8 · answered by Carlos R 1 · 1⤊ 0⤋