passes through (5,3) and parallel to y=2x-3?

Question

how would you do that

Answer 1

generic line equation:
y = mx + b

'm' is the slope of the line
'b' is the y value at which the line crosses the y-axis

you have a point, in your case this is '(5, 3)'.

you have a slope, in your case this is '2'.

you don't have a y-intercept; you need to find 'b'

y = m * x + b
3 = 2 * 5 + b
3 = 10 + b
-7 = b

your new equation is:
y = 2x - 7

A few things to note to help you understand...

Imagine if your slope was 0:
y = 0 * x + b
y = 0 + b
y = b

for all values of x, you would have a horizontal line where y = b (which makes sense since a horizontal line has no slope)

Answer 2

First make a simple graph. Then place the point (5,3) on the graph. Then, for the y=2x-3, you go down three and put a point. Then go up 2 and over one, up 2 over one etc. and connect the dots to make a line. Then you take the point at (5,3) and go down two and to the left one. *the opposite of the first* This should create a line parallel to y=2x-3.

I hope I helped!

Answer 3

If it's parallel, it'll have the same slope, which means the slope will be 2.

The y intercept will be -1

y=2x-1