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Write the expression ln(x) - 2ln(z) as a single logarithm expression. (In other words, trade in the expression ln(x) - 2ln(z) for an expression that looks like ln( ) .

2007-02-22 10:07:42 · 5 answers · asked by Samantha S 1 in Science & Mathematics Mathematics

5 answers

ln(x) - 2ln(z)

use power property
ln(x) - ln(z)^2

use quotient property
ln(x / z^2)

hope this helps

2007-02-22 10:12:01 · answer #1 · answered by      7 · 1 0

ln x-2ln z=ln(x/z^2)

2007-02-22 18:10:38 · answer #2 · answered by yupchagee 7 · 0 0

= ln[x/z^2]

2007-02-22 19:23:16 · answer #3 · answered by santmann2002 7 · 0 0

Remember the basic properties of logarithms

log(a * b) = log(a) + log(b)
log(a^n) = n * log(a)

You can use these properties to get
log(a/b) = log(a) - log(b)

so if you have log(x) - 2 log(z) then that's like

log(x) - log(z^2)

which is like

log(x / z^2)

2007-02-22 18:13:23 · answer #4 · answered by B H 3 · 0 0

ln(x/z^2)

Properties of logs
log(a)+log(b) = log(ab)
log(a)-log(b) =log(a/b)
log(a^n) = nlog(a)

2007-02-22 18:11:49 · answer #5 · answered by leo 6 · 0 0

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