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2 cos squared x+ sin x=2 [0,2pi]

2007-02-22 10:06:37 · 2 answers · asked by Anonymous in Science & Mathematics Mathematics

2 answers

2 cos ^2 x+ sin x=2
2 - 2sin^2x +sinx = 2
sinx(1-2sinx) = 0
x = 0, pi, 2pi, pi/6, 5pi/6

2007-02-22 10:11:16 · answer #1 · answered by sahsjing 7 · 0 0

2(1-sin^2x)+ sinx-2 =0 -2sin^2x +sinx =0 sin(x)*(-2sinx+1)=0

sin x= 0 x= 0 and x= pi ( -2sin x +1)= 0 sin x=1/2
x= pi/6 and x=5pi/6

2007-02-22 10:26:00 · answer #2 · answered by santmann2002 7 · 0 0

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