use the formula (y2-y1)/(x2-x1)
if say the x intercept is 1, then the point is (1,0)
say the y intercept is 5, then the point is (0,5)
y2=5
y1=0
x2=0
x1=1
So you have
(5-0)/(0-1)
5/-1
gives you -5 as the slope
2007-02-22 09:18:06
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answer #1
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answered by triveni1031958 3
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x intercept is a point on x axis so its coordinate is ( a , 0 )
and y intercept is on y axis so its coordinate is ( 0 , b )
so to find slope which is diff of y / diff of x
it is (b-0 )/(0-a) so it is -b/a
in numbers if x int is ( 3 , 0 ) and y int . is ( 0 , 5 ) slope = -5/3
you can also get equation of straight lineknowing only x , y intercept through formula ( x/a +y/b)=1
i hope this helps
2007-02-22 17:19:55
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answer #2
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answered by emy 3
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given x and y intercept and assuming that the equation is a line:
known: (x,0) and (0,y)
slope = Îy/Îx
= y-0/0-x
2007-02-22 17:18:28
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answer #3
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answered by Brian F 4
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If you have the points (a,0) and (0,b) the slope is
m= (b-0)/0-a) = -b/a
2007-02-22 17:18:39
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answer #4
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answered by santmann2002 7
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