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2007-02-22 09:12:54 · 4 answers · asked by granny smith 2 in Science & Mathematics Mathematics

4 answers

use the formula (y2-y1)/(x2-x1)
if say the x intercept is 1, then the point is (1,0)
say the y intercept is 5, then the point is (0,5)
y2=5
y1=0
x2=0
x1=1

So you have
(5-0)/(0-1)

5/-1
gives you -5 as the slope

2007-02-22 09:18:06 · answer #1 · answered by triveni1031958 3 · 0 0

x intercept is a point on x axis so its coordinate is ( a , 0 )
and y intercept is on y axis so its coordinate is ( 0 , b )
so to find slope which is diff of y / diff of x
it is (b-0 )/(0-a) so it is -b/a
in numbers if x int is ( 3 , 0 ) and y int . is ( 0 , 5 ) slope = -5/3
you can also get equation of straight lineknowing only x , y intercept through formula ( x/a +y/b)=1
i hope this helps

2007-02-22 17:19:55 · answer #2 · answered by emy 3 · 0 0

given x and y intercept and assuming that the equation is a line:
known: (x,0) and (0,y)
slope = Δy/Δx
= y-0/0-x

2007-02-22 17:18:28 · answer #3 · answered by Brian F 4 · 0 0

If you have the points (a,0) and (0,b) the slope is

m= (b-0)/0-a) = -b/a

2007-02-22 17:18:39 · answer #4 · answered by santmann2002 7 · 0 0

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