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5 answers

Yes because force is inversely proportional to the square of distances and proportional to the masses

2007-02-22 09:11:34 · answer #1 · answered by santmann2002 7 · 0 0

The gravitational force would NOT change if BOTH of the masses and the distance between them doubled. The force due to gravity is directly related to the product of the masses of the two particles and inversely proportional to the square of the distance between them. This is correctly modeled by the equation:

F = (GMm)/r^2

Lets say initally, we have masses M and m and distance r, as above
If everything is doubled:

new Force due to gravity = (G2M2m)/(2r)^2
new F = 4(GMm)/(4r^2)
The 4's cancel and we're left with:
new Force due to gravity = (GMm)/r^2 = previous Force due to gravity.

2007-02-22 17:19:54 · answer #2 · answered by John W 2 · 0 0

YES...

newtons theory of universal gravitation...

for example.. if two stars are in the universe their attraction to one another depends on their mass. Therefore, if you replace one of the stars with a star two times the size, the attraction is doubled.

the gravitational force between the two bodies will be very minute, but it is still there.

2007-02-22 17:09:25 · answer #3 · answered by Mojo 2 · 0 0

NO!!! Sorry I keep changing this. I'm confused, clearly.

Look at this formula.

F= G(m1xm2)/d^2

Let's say the mass is 5 g in the first one and 3 in the second... and the distance is 4 m.

F= 9.81(5x3)/4^2 = 9.197 N

So let's double all the numbers we plugged in.

F = 9.81(10x6)/8^2 = 9.197 N

No change. Hope this helps.

2007-02-22 17:18:40 · answer #4 · answered by hmbn 4 · 0 0

when the objects move twice as far apart, the gravity they exert on each other will be only 1/4 of the original amount. but the mass of the objects only doubles so each object will receive less gravity from the other ones.

2007-02-22 20:15:02 · answer #5 · answered by Tim C 5 · 0 0

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