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the titrationcurve was determined that at midpoint in the buffer region the ph was 4.50. what are pKa and Ka, please shows me work. thanks in advance

2007-02-22 08:46:59 · 1 answers · asked by phong pham 2 in Science & Mathematics Chemistry

1 answers

ph=pka+log(base/acid)
at midpoint base=acid
ph=pka+log1
so pka=ph=4.5
pka=-logka
ka=10^(-4.5)
typing the number then you got the answer

2007-02-25 13:01:01 · answer #1 · answered by Helper 6 · 0 0

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