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Question

Okay I am balancing equations in science and i really dont get what we are doing. I need to know what to do next because i am really lost. here is the problem:
AgNO(subscrpit 3) +Cu yield Cu(NO(little 3 at bottom)) (little 2) +Ag
I know that might be confusing but if you understand the problem can you plz help me with the next step?

Answer 1

AgNO3 + Cu --> Cu(NO3)2 + Ag

2AgNO3 + Cu --> Cu(NO3)2 + 2Ag

Answer 2

Balancing an equation is just making sure you have the same number of each type of atom before and after the reaction. This is necessary because, in chemical reactions, atoms are never created or destroyed so all the atoms you start out with must end up somewhere. A chemical reaction just changes which atom is boud to which. Your AgNO3 means that there is 1 silver (Ag) atom, 1 nitrogen (N) and 3 Oxygens (O). When you get Cu(NO3)2, that means that the coumpound has two of the NO3 groups for each copper. To start out balancing just do a 1 everywhere:

AgNO3 + Cu > Cu(NO3)2 + Ag

Everything is pretty balanced except for there is only one NO3 on the left and 2 on the right, so I need to put a 2 in front of the AgNO3 to have enough to go with the copper:


2 AgNO3 + Cu > Cu(NO3)2 + Ag

This is better but now there are 2 silvers (Ag) on the left and only one on the right. Now I need to make it so there are 2 silvers on the right, too.

2 AgNO3 + Cu > Cu(NO3)2 + 2 Ag

Finally check each side to se if it has the same number of each atom. Checking, you will see, 2 silvers, 2 nitrogen, 6 oxygen and 1 copper on each so so it is balanced.

Answer 3

Your goal is to add coefficients in front of some of the reactants and products so that you have the same number of each kind of atom on both sides. As written, you have one N and three O on the left, but two N and six O on the right, so you're not balanced. The most noticeable thing is that you have NO3 on the left but (NO3)2 on the right. I'd start by giving the reactant AgNO3 a coefficient of 2. But now you have 2Ag on the left and just Ag on the right, so give the product Ag a coefficient of 2 as well. You'll then find that the equation is balanced. On each side, you have two Ag, two N, six O, and one Cu. Balancing equations is part of stoichiometry, and it comes down to glorified trial and error.

Answer 4

The goal in balancing equations is to end up with the same numbers of every element on both sides of the arrow.

In this equation, you have one Ag on each side, one Cu on each side but you've got 2 nitrate ions (NO3-) on the right and only one on the left. So, you need to put a two in front of AgNO3 on the left. Now, that gives you two Ag on the left and only one on the right, so you need to put a two in front of Ag on the right.

Then, the equation is balanced.

Think about ions as a single thing, unless they change in the reaction (so, deal with NO3- as a thing rather than dealing separately with N and O).

Hope this helps.

Answer 5

You want to make there be an equal number of an element (for every element/compound), so you need to add coefficients.
The balanced equation for this one is:
2AgNO(3) + Cu yields Cu(NO(3)(2) + 2Ag