Algebra--Consecutive Odd integers?

Question

The sum of three consecutive ODD integers is five less than twice the smallest of these integers.
Find the smallest of these integers AND find the greatest of these integers.

Answer 1

Your numbers are 2k+1,2k+3,2k+5
smallest 2k+1, so

(2k+1)+(2k+3)+(2k+5) +5= 2(2k+1)

6k+14=4k+2

2k+12=0

so k=-6

smallest : 2*(-6)+1=-11

greatest 2*(-6)+5=-7

Answer 2

ok, i do no longer understand each and all of the stairs and stuff. yet it fairly is how I figured it out. First, I divided fifty six by potential of four. Then, I incredibly have 14 through fact the widely used. So, I positioned it as a recommend and grew to become it into atypical numbers. One much less of 14 is 13. one extra of 14 is 15. 3 much less of 14 is 11 and 3 extra of 14 is 17. So the solutions is 11, 13, 15, 17. wish it help. Sorry, i do no longer remember a thank you to do it.

Answer 3

x+(x+2)+(x+4)=2x-5

use that as a guideline.. but don't count on it as being fully correct...