x2 – 6x + 8
x2 – 4
This is a fraction, x^2 - 6x + 8 over x^2 - 4
2007-02-22 06:58:36 · 5 answers · asked by spanishfly_100 1 in Science & Mathematics ➔ Mathematics
1) (x-2) (x-4)
2) (x+2)(x-2)
3) (x-4)(x-2)/(x+2)(x-2)
= (x-4) / (x+2)
hope this helps
2007-02-22 07:03:12 · answer #1 · answered by Curious G 2 · 0⤊ 0⤋
x2 will cut of x2 by 1
4 will cut of 8 by 2
So I think the reminder will be 6x + 2
2007-02-22 15:05:41 · answer #2 · answered by Muhammad Faraz Quadri 2 · 0⤊ 0⤋
Taht wil equal to: [(x-2)(x-4)] / [(x-2)(x+2)]
after the x-2 on top cancel with the x-2 at the bottom. the answer will be: x-4/x+2
2007-02-22 15:20:28 · answer #3 · answered by sweet113509 1 · 0⤊ 0⤋
= (x -4) (x-2) / ( (x -2) (x + 2) ) = (x-4)/(x + 2) for x != 2 (undefined for x = 2)
= (x + 2 - 6)/(x + 2) = 1 - 6/(x + 2) for x != 2, -2
2007-02-22 15:05:23 · answer #4 · answered by Vijay Krishnan 1 · 0⤊ 0⤋
Factorize top and bottom
(x-4)(x-2)
(x-2)(x+2)
(x-2) cancels to make 1
so we now have
(x-4)/(x+2)
2007-02-22 15:07:58 · answer #5 · answered by Kristina P 2 · 0⤊ 0⤋