ok here we go. i've tried but failed to get this at all.
a car left point X at noon traveling along a straight road at exactly 60 miles per hour. It arrived at point Y at 1:00pm on the same day. When this car was at point M, halfway between X and Y , a second car traveling at exactly 45 miles per hour left point X and traveled toward point Y along the same road. how far had the second car travled when the first car reached point Y?
X----------M----------Y
ok thats it i love u guys!!!!
2007-02-22 06:55:49 · 4 answers · asked by QueenVicky 2 in Education & Reference ➔ Homework Help
22.5 Miles
It took the first car 1 hour to travel the distance at 60 MPH. SO you assume it is 60 Miles. It takes the car 30 min. to travel the last part, The secound car travels 45 MPH for a half hour so 45 / 2 = 22.5 Miles
2007-02-22 07:04:34 · answer #1 · answered by Anonymous · 1⤊ 0⤋
The answer is 22.5 miles.
The first sentence basically tells you that the first car travels 60 miles in 60 minutes, which means that it travels 30 miles in 30 minutes.
So, the question is really asking how far a car going 45 miles per hour can travel in 30 minutes.
45 miles x 1 hour x 30 minutes = 22.5 miles
per hour per 60 minutes
2007-02-22 07:10:41 · answer #2 · answered by Mattofep 2 · 0⤊ 0⤋
22.5 mi.s
The 1st car took an hour to get to Y. So, M being halfway took 30 mins. If the 2nd car was doing 45mph then he went half that in a half hour.
2007-02-22 07:08:36 · answer #3 · answered by Fordman 7 · 0⤊ 0⤋
I calculated it and its the same thing wut Sean answerd
45 / 2 = 22.5 Miles
2007-02-22 07:10:39 · answer #4 · answered by Anonymous · 0⤊ 0⤋