Pythagorean THereom problem 2?

Question

a support cord is fastened to a pup tent and to the ground. if the tentiis 1.2m high and the cord is 2.3m long, how far is the end of the cord from the tent?

Answer 1

a² + b² = c²

a is the height of the tent
b is the distance of the end of the cord from the tent
c is the length of the cord

(1.2)² + b² = (2.3)²
b² = (2.3)² - (1.2)²
b² = 5.29 - 1.44
b² = 3.85
b = √3.85

b = 1.96m

Answer 2

well, c^2 = a^2 + b^2

this case c is the hypothenes, so its 2.3 m

2.3m^2 = 1.2m^2 + b^2

b^2 = 2.3m^2 - 1.2m^2

b^2 = 5.29m^2 - 1.44m^2

b^2 = 3.85m^2

b = 1.96 m

the end of the card from the tent is 1.96 m

Answer 3

let a m be the tentiis
b m be the cord
c m be the distancefrom the end of the cord to the tent
a^2+b^2=c^2
1.2^2+2.3^2=c^2
c=2.6m

Answer 4

Hi. You again have two sides, the vertical 1.2 and the hypotenuse 2.3. The horizontal will be the square root of (2.3 x 2.3) - (1.2 x 1.2) .

Answer 5

almost exactly 2m (square root of 3.97)

1.2 squared + 2.3 squared = x squared
1.44 + 2.53 = x squared
3.97 = x squared
sqr rt of 3.97 = x = almost 4
x almost 4 (sqr rt of 4 = 2)

Answer 6

hi you've 2 sides, 15 and 25 (cm, miles, lightyears... no distinction). locate the hypotenuse (15x15 + 25x25, take the sq. root of the the answer.) 15+25 is lengthy way round, hypotenuse is the shortcut.

Answer 7

it will be

square root of (2.3 squared times 1.2 squared)

square root of (3.86)

1.96 meteres

Answer 8

1.2 ^ 2+2.3 ^ 2= c^2
1.44+5.29= c^2
6.73=c^2
sqrt of 6.73 = c
2.5942=c

Answer 9

c^2=1.2^2+2.3^2
c^2=1.44+5.29
c^2=sqrt of 6.73
c=2.59
c=2.6

Answer 10

2.5942243542145694689507875815343

Square both measures, add them and take the square root of your sum.