A pacemaker sends a pulse to a patient's heart every time the capacitor in the pacemaker charges to a voltage of 0.20 V. It is desired that the patient receive 66 pulses per minute. Given that the capacitance of the pacemaker is 110 µF and that the battery has a voltage of 9.0 V, what value should the resistance have?
I think I keep solving for R wrong. The time should just be 66/60, right?
2007-02-22 06:22:28 · 3 answers · asked by ANT-a-gonistic 3 in Science & Mathematics ➔ Physics
The question is already in pulses per minute. If I need the time, don't I divide by 60 instead?
2007-02-22 07:27:55 · update #1
R = V*sec/Q
Q = 110microF =.00011F; V=9 and s=66/60=1.1
R = 9*1.1/.00011 = 90000 ohms = 90 kilo-ohms
2007-02-22 15:49:28 · answer #1 · answered by DuckyWucky 3 · 0⤊ 0⤋
If you want 66 pulses per minute then the time between pulses should be 60/66 seconds. If you assume that the capacitor is instantly discharged back to 0V then this is the time you are looking for.
2007-02-22 07:10:09 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Why don't you call Medtronics, they are there to help
2007-02-22 06:30:16 · answer #3 · answered by Icey 5 · 0⤊ 0⤋