Using the same method I showed you in your last question:
h² = 1.4² + 4²
√(h²) = √(1.4² + 4²)
h = √(1.4² + 4²)
h = √(17.96)
This is approximately 4.2, but certainly isn't exactly 4.2.
2007-02-22 05:45:05
·
answer #1
·
answered by Anonymous
·
0⤊
0⤋
h^2 = 1.4^2 + 4^2
h^2 = 1.96+16
h = √(1.96+16)
h = √17.96
h = 4.237924020083418154343531790304...
2007-02-22 05:58:40
·
answer #2
·
answered by math freak 3
·
0⤊
0⤋
the formulae is: a^2=b^2+c^2 therefore'
1.4^2=1.96 and 4^2=16 so u would add the two and get
1.96+16=17.96.
h^2=17.96
h=sq.rt of 17.96=4.2
h2=4.2x2=8.4
2007-02-22 05:50:50
·
answer #3
·
answered by Gud Girl 1
·
0⤊
0⤋
√h² = √(1.4)² + (4)²
√h² = √1.96 + 16
√h² = √17.96
h = 4.23792402
h = 4.2 Rounded to one decimal place
- - - - - - - - - s-
2007-02-22 06:10:43
·
answer #4
·
answered by SAMUEL D 7
·
0⤊
0⤋
h^2 = 1.4^2 + 4^2 = 1.96 + 16 = 17.96 =>
h = sqrt(17.96) = 4.24
2007-02-22 05:45:32
·
answer #5
·
answered by Anonymous
·
0⤊
0⤋
Yes h^2 = 4.2
2007-02-22 05:43:37
·
answer #6
·
answered by Lu 1
·
0⤊
1⤋
Mulitply it out
1.4^2 according to my calculator is 1.96
4^2 is 16
16 + 1.96 = 17.96, so take the square root of that and you get 4.237
2007-02-22 05:46:41
·
answer #7
·
answered by sarge927 7
·
0⤊
0⤋
Multiply 1.4 times itself... that's 1.4²
Mulitply 4 times itself.... that's 4²
Add them together and take the square root.
2007-02-22 06:16:07
·
answer #8
·
answered by Anonymous
·
0⤊
0⤋
quadratic formulation: i won't be in a position to actual sort it, so indexed right here are the words: damaging b plus or minus the sq. root of b squared minus 4ac, throughout 2a pythagorean theorem: a^2+b^2=c^2
2016-12-17 16:20:14
·
answer #9
·
answered by dricketts 4
·
0⤊
0⤋
h^2=1.96+16
h^2=17.96
h^2=4.23
If you round it off it would be 4.2
2007-02-22 06:59:36
·
answer #10
·
answered by Anonymous
·
0⤊
0⤋