English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

electric field lines emitted by a charge are infinite then why does GAUSS theorem say electric flux related to a closed surface
having charge q inside it =q/epsilonzero

2007-02-22 05:31:08 · 4 answers · asked by RAM KRISHNA MISHRA 1 in Science & Mathematics Physics

4 answers

When you visualize a field using field lines they are spaced so that each line represents the same flux {E x area } so they are closely spaced where the field is strong and widely spaced where the field is weak . Since it is an arbitrary choice what flux a line represents, you can increase the number of lines as much as you chose by decreasing the area for each line so that (E x area) is still the same for each line. The sum for the fluxes over a closed surfaces will not be changed

2007-02-22 13:02:01 · answer #1 · answered by meg 7 · 0 0

Electric field lines aren't infinite. They are infinite in length, but not in number. The greater the number of electric field lines, the greater the charge. The number of electric field lines corresponds to the magnitude of the charge.

2007-02-22 13:39:31 · answer #2 · answered by Ryan S 2 · 0 0

Electric field lines do not exist. They are only a graphical invention to help people visualize things.

2007-02-22 13:52:09 · answer #3 · answered by Gene 7 · 0 0

we cannot grasp electric field by any one of our senses but we can detect it using a charged body,hence to represent it we draw lines( the way I am doing it now to communicate to you).As alphabets are written as per rules e.g if I say this g is tee(t) you will not agree and you will insist that it is gee and not tee,hence electric field is represented by drawing lines according to some rules.

2007-02-27 11:27:07 · answer #4 · answered by ukmudgal 6 · 0 0

fedest.com, questions and answers