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the question is

14 exponent 2 = c exponent 2 + 8 exponent 2

whati s the formula ? how do i solve the missing side.

2007-02-22 05:16:45 · 8 answers · asked by Anonymous in Science & Mathematics Mathematics

8 answers

formula:
a^2+b^2=c^2+2ab*cos θ

in this case, it is assumed that θ = 90 deg

a^2+b^2=c^2+2ab*cos 90 deg
a^2+8^2=14^2+2ab*0
a^2+64=196+0
a^2=196-64
a=√(196-64)
a=11.489125293076057319701222936438...

2007-02-22 05:22:48 · answer #1 · answered by math freak 3 · 0 0

Since you ask: the Pythagorean Theorem states that for a right triangle, the sum of the squares of the two legs is equal to the square of the hypotenuse. Or if "a" and "b" are the lengths of the two legs and "c" is the length of the hypotenuse, then a^2 + b^2 = c^2.

But your question here is more of an algebra question. You have this: 14^2 = c^2 + 8^2, and you want to solve for c.

As always, get all of your variable terms on one side. In this case, just subtract 8^2 from both sides:
14^2 - 8^2 = c^2

To get rid of the square on the c, you perform the operation that gets rid of squares: the square root!
c = √(14^2 - 8^2)
c = √132

2007-02-22 05:38:20 · answer #2 · answered by Anonymous · 0 0

14^2 =c^2 + 8^2 this is pythagorean formula
square all of the numbers
196 = c^2 +64
to solve for the missing side, subtract 64 from both sides of the equation and take the square root of the difference.
c = sqrt ( 196 - 64 )

in general the hypotenuse is usually labeled with the variable "c". But not in the case of your problem. c represents the length of one of the sides.

2007-02-22 05:26:54 · answer #3 · answered by Ray 5 · 0 0

14^2=c^2+8^2 First subtract 8^2 from both sides
14^2-8^2=c^2
196-64=c^2
132=c^2
c can be the positive or negative square root of 132 because either will work in the origianl equation (because c is squared)..Always check your answer by plugging it back into the original problem.

2007-02-22 05:26:26 · answer #4 · answered by bbdean2002 1 · 0 0

The Pythagorean theorem states: (key this formula only works with right angle triangles)

a^2 + b^2 = c^2 or c= sqrt(a^2 +b^2)

if you are solving for b, which is what it looks like from the way your equation is written, then:

b = sqrt(c^2 - a^2)

2007-02-22 05:29:04 · answer #5 · answered by grk_tigris 3 · 0 0

14^2=c^2+8^2
196=c^2+64
196-64=c^2+64-64
132=c^2
sqrt of 132=c
answer 2 x Sqrt of 33

2007-02-22 06:08:30 · answer #6 · answered by Dave aka Spider Monkey 7 · 0 0

196=c^2+64 (subtract 64)
132=c^2 (take the square root)
c=2 sqrt33

2007-02-22 05:21:56 · answer #7 · answered by Al3xa 2 · 0 0

=sqrt(14^2-8^2)=11.48

just use algebra, subtract 8^2 from both sides and the square root both sides, then solve

2007-02-22 05:20:39 · answer #8 · answered by Jason P 1 · 0 0

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