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I think I know how to do it but im not complety sure could i have some help?

5<-x/2

and

3.4x<13.6?

2007-02-22 04:13:41 · 4 answers · asked by Anonymous in Science & Mathematics Mathematics

4 answers

1) Multiply both sides by 2

5 < -x/2
5*2 < -x
10 < -x
-10 < x

2) Divide both sides by 3.4

3.4x < 13.6
x < 13.6/3.4
x < 4

2007-02-22 04:32:09 · answer #1 · answered by math freak 3 · 0 0

5<-x/2.......(i)
3.4x<13.6...(ii)
Equation No. i
5<-x/2
5*2<-x
10<-x
-10 Equation No. ii
3.4x<13.6
x<13.6/3.4
x<4 .......(iv)

so combining Equation iii and iv

10 so x=5,6,7,8, and 9

2007-02-22 05:13:07 · answer #2 · answered by mohammadali_da_gun_of_2006 1 · 0 0

So, you're trying to solve for X?

Fair enough.

Remember that with inequalities, you need to change the sign if you multiply or divide by negative numbers across the inequality symbol.

Let's do the first one:
5 < -x/2

The first thing you need to do is multiply both sides by 2, to get x by itself

10 < -x

Then you divide both sides by negative one, so that X is positive.

-10 > x

There you go. All done.

The second one is much simpler, it's simple algebra, and the inequality symbol doesn't need to change.

2007-02-22 04:20:57 · answer #3 · answered by Brian L 7 · 0 0

5 < -x/2
Multiply both sides by 2:
10 < -x
Add x to both sides:
10 + x < 0
Subtract 10 from both sides:
x < - 10

3. 4x < 13.6?
Divide both sides by 4
x < 3.4

2007-02-22 04:23:44 · answer #4 · answered by Helmut 7 · 0 0

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