suppose you have an object that is a rectangular cylinder. it has a base area of 6cmsquare and a height of 8cm.
2007-02-22 03:30:11 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Physics
I suspect you mean a "right circular cylinder", not a rectangular one! The number of blocks it will hold is 24. See below:
Area of base = (pi) * (r) * (r) = 6 cm3.
Therefore, base diameter = 2 * (r) = 3.8197 cm
The cylinder (which is 8 cm tall) will hold 3 * 8 = 24 blocks that are 1cm3.
This assumes, of course, that you must have 'complete' blocks, not partial ones.
2007-02-22 03:45:16 · answer #1 · answered by CanTexan 6 · 0⤊ 0⤋
If it has an area of 288 cm^3 then surely 288 blocks fit in it.
I answered the same question a minute a go. (for the volume)
2007-02-22 03:35:03 · answer #2 · answered by Doctor Q 6 · 0⤊ 0⤋
The volume is 64 cc.
However, because your blocks are cubic, and the cylinder is rounded, it will not hold 64 cubes .. which has straight edges.
2007-02-22 03:40:13 · answer #3 · answered by Norrie 7 · 0⤊ 0⤋
About 32 square blocks can fit into it.
See the below image I have made for explanation.
http://i16.tinypic.com/2mzbejd.gif
2007-02-22 03:56:24 · answer #4 · answered by Rohan 2 · 0⤊ 0⤋