What is the thermal energy?

Question

In a linear accelerator, protons are accelerated from rest through a potential difference to a speed of approximately 2.69x10^6 m/s. The resulting proton bean produces a current of 1.03x10^-6 A. The mass of the proton is 1.67x10^-27 kg. and its charge on the proton is 1.6x10^-19 C. If the beam is stopped in a target, determine the amount of thermal energy that is produced in the target in one minute. Answer in units of J.

Answer 1

If all the energy of the photon were transferred to the target I beleive the formula would be
1/2 * Mass * Velocity^2

Answer 2

I'm not doing this one as it's too easy.....

Just work out how many Protons per second will hit the target if they are travelling at 2.69x10^6 m/s.......

The use K.E. = 1/2 m v^2 (for the Energy of One Proton) then multiply this by the number of Protons you worked out before (gives you the energy per second).

Then multiply this result by 60 (as its in a minute isn't it??)

OK OK - You have 2.69x10^6 protons hitting the target per second (it is a beam)

K.E. = 1/2 m v^2 = 1/2 x 1.67 x 10^-27 x (2.69 x 10^6)^2

K.E. = 6.0421435 x 10^-15 Joules (per proton)

In 1 second we have 2.69 x 10^6 Protons, therefore you have-:

2.69 x 10^6 x 6.0421435 x 10^-15 = 1.6253366 x 10^-8 Joules per second.

In one minute (x 60)

1.6253366 x 10^-8 x 60 = 9.752 x 10^-7 Joules per minute

Answer 3

hehe.. is this ur assignment question huh? give me the formula and i can solve it~ lol i forgot the formula.