Determine the potential difference through which the protons were accelerated.?

Question

In a linear accelerator, protons are accelerated from rest through a potential difference to a speed of approximately 2.69x10^6 m/s. The resulting proton bean produces a current of 1.03x10^-6 A. The mass of the proton is 1.67x10^-27 kg. and its charge on the proton is 1.6x10^-19 C. Determine the potential difference through which the protons were accelerated. Answer in m/s.

Answer 1

This is an easy one for a Atomic & Nuclear Physicist-:

q V = 1/2 m v^2

(V is potential, v is velocity, m is mass, q is charge on particle)

1.6 x10^-19 x V = 1/2 x 1.67x10^-27 x (2.69x10^6)^2

Therefore V = 6.0421435 x 10^-15 / 1.6 x 10^-19

V = 37763.39688 Volts of Potential

Bingo my good man - you don't even need the current value.

Answer 2

is this a trick question? no longer some thing can pass faster than the speed of sunshine, it really is what would ensue to the article if it underwent uniform acceleration, until eventually your body of reference is accelerating, in which case the finest speed will be unobservable.