an airplane is dropping supplies to a village. it is flying at an altitude of 785 metres and at a constant horizontal velocity of 53.5m/s. at what horizontal distance before the drop point should the co-pilot drop supplies so that they will land at the drop point?
2007-02-22 01:54:37 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Physics
The supplies will fall 785 m under the influence of gravity, starting from rest.
h = v0t + ½ g t²
t = squareroot(2*h / g)
= squareroot(2*785m/9.8m/s²)
= 12.66 seconds
During this free fall time, the package will continue with its initial horizontal velocity of 53.5 m/s. During this time, it will travel a distance given by
x = v*t
= 53.5 m/s * 12.66 s
=677 m
So the pilot should release the package 677 meters before he is above the target. All of this assumes that there is no wind resistance.
2007-02-22 02:06:13 · answer #1 · answered by Grizzly B 3 · 1⤊ 0⤋
Grizzly is correct in his math analysis but in addition to wind, there is the question of DRAG. In the real world, the supplies at that altitude would be dropped by parachute.
2007-02-22 02:12:27 · answer #2 · answered by minorchord2000 6 · 0⤊ 0⤋
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2016-12-04 19:13:11 · answer #3 · answered by Anonymous · 0⤊ 0⤋
the point is when the driver sees the ground to drop the shipments and a clear space to drop them in.
2007-02-22 01:59:07 · answer #4 · answered by sunflare63 7 · 0⤊ 1⤋