how is the graph of y=x^2 + 5x + m (where m is a real number) realted to the graph of y=x^2?
Please pleas help!
2007-02-22 01:47:21 · 4 answers · asked by Swishswishswish 2 in Science & Mathematics ➔ Mathematics
oh, i meant Related not Realted. just a typo.
HELP!
2007-02-22 01:47:52 · update #1
The graph of y=x^2 + 5x + m is the graph of y+x^2 moved to the left 2.5 and vertical whatever m - 6.25 turns out to be.
2007-02-22 02:01:05 · answer #1 · answered by Goose 1 · 0⤊ 0⤋
I am not sure what you are looking for, but if you set them equal to each other then both of the graphs cross at x=-m/5
x^2 + 5x + m=x^2
5x + m=0
5x=-m
x=-m/5
2007-02-22 01:52:23 · answer #2 · answered by Jason P 1 · 0⤊ 1⤋
if all you need to do is resolve for x from 2.5x^2-12.5x then i think of the respond is x=5 properly i used my calculator yet you need to use the quadratic formula 2.5x^2 -12.5x = 0 x= -b+/- Sqrt(b^2-4ac) / 2a a=2.5 b=-12.5 c=0 plug in the values and additionally you gets 2 values; x=5 and x=0 and 0 ovbiously isnt the respond reason it cant be
2016-10-16 05:59:34 · answer #3 · answered by ? 4 · 0⤊ 0⤋
DO YOUR OWN HOMEWORK !!!!!!!!!!!!!
2007-02-22 01:56:00 · answer #4 · answered by tire chick 4 · 0⤊ 0⤋