physics help?

Question

a person drops a Chianti bottle from the top of a vertical tower 52.2 m tall. How long does it take for the bottle to fall to the ground?What is the velocity of the bottle as it hits the ground?

Answer 1

for 1st part of problem use formula

S(52.2)=.5*g(acceleration due to gravity)*t(time)^2
so only one unknown....(??wats that???) RIGHT!!

for second part use the time calculated in 1st part
and apply
V(velocity)=g*t.

Well u can also apply(for 2nd part) V^2=2*g*S(52.2)

well physics is very interesting!!!!!!!!!!!!
NO?

Answer 2

in the problem,

the initial velocity of the bottle, u = 0 m/s
distance, s = 52.2 m
gravitational acceleration, g = 9.8 m/s^2
time, t = ?
final velocity, v = ?

s = ut + 1/2gt^2

or, 52.2 = 0 + 1/2 * 9.8 * t^2
or, t = 3.264 sec

so, time required for the bottle to fall to the ground = 3.264 second

v = u + gt

or, v = 0 + 9.8 * 3.264
or, v = 31.98 m/s

velocity of the bottle when it hits the ground = 31.98 m/s

Hope this was helpful.

Answer 3

Take t as the time taken for the bottle to fall to the ground. The free fall acceleration is 10ms^(-2). Draw out a graph, I think it'll be easier.

I'm rather busy now, but if you still don't understand email me or comment and I'll help you with it tomorrow.

Answer 4

s = ut + 1/2 at^2
a) 3.2622 seconds to hit the deck

v= u + at
b) 32.0026 metres per second (when it hits the deck)

You should use Newton's equations of motion

Answer 5

5.3265306122448979591836734693878 seconds at poles and longer duration at equator. 9.8 m/s at poles and slower at equator.