I have a question for chemistry. It is for my pre-lab. Could someone explain this to me.?

Question

If you started with 42.8 g of sucrose, how many grams of ethanol could be obtained from the reaction below?

C12H22O11 + H2O --> 4 C2H5OH + 4 CO2 (g)

Answer 1

A mole of sucrose is 177g (12*12 + 22*1 + 16*11). The reaction has 0.242 moles which would result in 0.242 * 4 = 0.968 moles of ethanol.

A mole of ethanol is 46.0g (2*12 + 6*1 + 1*16). This reaction produces 46.0 * 0.968 = 44.5g of ethanol (to 3 sig figs).

This is 56 ml...a nice healthy shot of grain.