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If you started with 42.8 g of sucrose, how many grams of ethanol could be obtained from the reaction below?

C12H22O11 + H2O --> 4 C2H5OH + 4 CO2 (g)

2007-02-22 00:06:40 · 1 answers · asked by Dan 2 in Science & Mathematics Chemistry

1 answers

A mole of sucrose is 177g (12*12 + 22*1 + 16*11). The reaction has 0.242 moles which would result in 0.242 * 4 = 0.968 moles of ethanol.

A mole of ethanol is 46.0g (2*12 + 6*1 + 1*16). This reaction produces 46.0 * 0.968 = 44.5g of ethanol (to 3 sig figs).

This is 56 ml...a nice healthy shot of grain.

2007-02-22 00:16:56 · answer #1 · answered by gebobs 6 · 1 0

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