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Pb(NO3)2 + 2KI ----> PbI2 + 2KNO3

Now the PbI2 is a yellow precipitate, and the KNO3 is aqueous, so the ionic equation is:

Pb2+(aq) + 2I-(aq) ------> PbI2(s)

2007-02-23 09:10:22 · answer #1 · answered by Gervald F 7 · 0 0

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