Either a micrometer or vernier caliper depending on the thickness. If it is more than about 1cm - a vernier should be used, anything thinner the micrometer is more accurate.
Unless you use an optical microscope with a measurement graticule.
2007-02-21 22:06:15
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answer #1
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answered by Doctor Q 6
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You measured the diameter of the wire in order to determine its cross-sectional area (CSA). If the diameter = d, then the CSA = pi.d²/4. Hence, the %-age error in d has caused an %-age error in A of twice as much, since A is proportional to d². Let me explain . . . . . . . . . Let the error in d = δd So the actual measurement of d = (d + δd). Let the resultant error in A = δA. Then the resultant value of A, with that error = (A + δA) But we know that the CSA, A = kd², where k = pi/4 and d = the actual diameter. Therefore, (A + δA) = k.(d + δd)². Therefore, δA = k.(d + δd)² - A = k.(d + δd)² - kd². So: δA = [kd² + 2k.d.δd + k(δd)²] - kd² Since (δd)² is a very tiny quantity, we can ignore it for all practical purposes and equate it to zero. Therefore: δA = [kd² + 2k.d.δd] - kd² = (k.d).(2.δd.) Hence, δA / δd = 2.k.d Thus the size of the error in d produces twice the size of the corresponding error in A. So to determine the resultant error in A, the known error in d must be doubled.
2016-04-03 01:26:58
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answer #2
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answered by Teresa 4
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To be precised the most commonly used tool for measuring in industry would be an "Outside Micrometer"
its accuracy is commonly .001 in.
2007-02-22 20:41:56
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answer #3
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answered by Anonymous
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A micrometer
2007-02-21 23:16:56
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answer #4
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answered by burning brightly 7
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A micrometer is the best instrument as it is the most precise.
2007-02-21 23:20:46
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answer #5
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answered by Tiger Beer 2
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A micrometer calliper?
2007-02-21 21:47:16
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answer #6
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answered by Labsci 7
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Screw Guage or Vernier Caliperse
2007-02-21 23:43:33
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answer #7
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answered by GS 3
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Micrometer or the Screw gauge.
2007-02-21 22:28:50
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answer #8
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answered by Anonymous
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I agree
2007-02-21 23:19:47
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answer #9
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answered by Comfortably Numb 3
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micrometer
2007-02-21 21:50:16
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answer #10
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answered by Anonymous
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