1)
For each shirt less than $100 each,
$1_93.4_ < $100 x 12
$1_93.4_ < $1200
we know first empty digit shall be 1
As there is only 2 decimal point for total value,
only 1193.46 / 12 = 99.455
or 1193.40 / 12 = 99.45
others cannot be divided by 12 completely
So, for two decimal point, one short shall cost $99.45
The missing figure is $1193.40
2)
Let say the length of paddock = l
the width of paddock = w
l * w = 3380 (Area)
l = 3380/w ---(1)
2(l + w) = 234
l + w = 117
from (1)
3380/w + w = 117
3380 + w^2 = 117w
w^2 -117w + 3380 = 0
(w - 65) (w - 52) = 0
w = 65 m, w = 52 m
width (w) < length (l)
width = 52 m
length = 65 m
The longer sides is 65 m
2007-02-21 21:46:12
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answer #1
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answered by seah 7
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Solution to Question[1]
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As Georgina knows that the shirts cost less than $100 each, the total cost is less than $100 x 12 = $1200
So there are only 2 possibilities for the first blank space, 0 or 1
i.e. 1093.4_ or 1193.4_1193
We know that Mod(1093,12)=1 and Mod(1193,12)=5
and the remainders are 1.4_ and 5.4_.
To be able to divide exactly with only 2 precision points, the possible values can be 1.44 and 5.40.
So the total cost can be either 1093.44 or 1193.40
giving us the possibility of cost of each shirt to be either 91.12 or 99.45
Solution to Question[2]
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Let us say the sides are a & b, the longer side being a.
Given Perimeter, 2(a+b)=234 =>a+b=117 ---- Conclusion(1)
If a were to be the longer side, it cannot be less than (a+b)/2.
i.e., a > (a+b)/2 which is a >58.5 ---- Conclusion (2)
Given Area, a.b=3380 ---- Conclusion (3)
Because the product of a & b does not have a number after the decimal place, a or b cannot have one after the decimal place. ---- Conclusion (4)
And because the product of a & b ends with 0, a and b must end with 0,2 or 5. ----- Conclusion (5)
From conclusion (2) & (5), possible values for a --- 60, 62, 65, 70, 72, 75, 80, 82,.........115.
But from conclusion (1) & (3), a = 65, b=52.
So Mr Morrison needs 65 m of fencing if he wants to fence once of the longer sides.
2007-02-22 07:29:30
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answer #2
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answered by GS 3
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Answer to the second question:
2. This is very simple. Let L and B be the length and width of the paddock respectively.
Perimeter = 2 * (L + B) = 234
L + B = 117....................Equation 1
Area = L * B = 3380....................Equation 2
From Equation 1, we have B = 117 - L
Substituting this in Equation 2, we get:
L * (117 - L) = 3380
=>L^2 - 117L + 3380 = 0
Solving, we get L = 65, 52.
Substituting one of the above values in Equation 1 and solving for the other, we get B = 52, 65.
Hence, the dimensions of the paddock are 52m, 65m.
2007-02-22 05:42:51
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answer #3
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answered by Shashi 2
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Q.1) Each shirt cost is $99.45 and the total cost is $1193.40.
Q. 2)
Let a and b be length and width of rec.
therefore,
2*(a + b) = 234 ...........(1)
a + b = 234/2 = 117
a = 117 - b ...................(2)
a*b = 3380
a*(117 - a) = 3380
117a - a^2 = 3380
a^2 - 117a + 3380 = 0
a^2 - 65a - 52a + 3380 = 0
(a - 65)(a - 52) = 0
a = 65 or a = 52
since a is a longer side therefore
a = 65m
2007-02-22 07:32:44
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answer #4
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answered by Anonymous
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#1
We know the first part of the total needs to be either 1193 or 1093. (12*100 = 1200, so it has to be less than that.)
So, by trial and error, I get two possible solutions:
1193.40 / 12 = 99.45
1093.44 / 12 = 91.12
Without more information, we can't narrow it down.
#2
width = x
length = y
xy = 3380
2x + 2y = 234
2y = 234 - 2x
y = 117 - x
x(117-x) = 3380
117x - x^2 = 3380
0 = x^2 - 117x + 3380
0 = (x - 52)(x - 65)
x = 52, y = 65
or
x = 65, y = 52
He needs 65m of fencing for one of the longer sides.
2007-02-22 05:51:38
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answer #5
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answered by Mathematica 7
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Question 1-:
If you already know they are less than $100 - we can assume that the second digit is 0 or 1. If it is 1 then the shirts are around $99.xx each.
Cost of shirts are $99.45
12 x 99.45 = $ 1193.40
2007-02-22 05:49:46
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answer #6
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answered by Doctor Q 6
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question:2
let length be:x
let width be:y
then: xy=3380
and: 2x + 2y = 234
so sloving for x and y
and then longer side =x
2007-02-22 05:37:55
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answer #7
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answered by Doc_Cain 1
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