A pitcher throws a .142kg baseball at 47.2 m/s. As it travels a distance of 19.4m, the ball slows to 42.5 m/s because of air resistance. Find the change in temperature of the air through which the ball passes. The following assumptions may be made: molar specific heat of air is (7R/2), molar mass of air is 28.9 g/mole, and the cover insulates the interior of the ball so the ball's temperature does not change. The temperature change happens in a cylinder of 19.4m length and radius of 3.7cm. Air temperature is 20 degrees Celcius.
2007-02-21 14:35:33 · 1 answers · asked by Shane W 1 in Science & Mathematics ➔ Physics
The energy lost by the ball due friction =.142(47.2^2-42.5^2)
The volume of air 19.4 pi .037^2
Find how many moles M in volume at 20 degrees--Standard volume of 1 mole of an ideal gas at STP: 22.4 liters
Then energy loss = M C ( change in T)
2007-02-21 16:23:43 · answer #1 · answered by meg 7 · 0⤊ 0⤋