A ball is shot into the air from a bridge, and its height, y, in feet, above the ground t seconds after it is thrown is given by y=f(t) = −16t2 + 55t + 34. Answer the following questions. Round your answers to two decimal places in the first three questions, and one decimal place in the last question.
B. What is the average velocity of the ball during the first second?
Answer: feet/second
D. Graph the function f(t) in your calculator. From the graph estimate the maximum height the ball will reach.
Answer: feet
2007-02-21 14:16:42 · 1 answers · asked by J R 2 in Education & Reference ➔ Homework Help
B. Based on your function, the ball begins at a velocity of 55 fps. It decelerates at 32 fps/s, so after the first second its velocity is 23fps. Average = (55 + 22)/2 = 38.5 fps
D. You don't need to estimate. You can figure out how long it takes to reach zero velocity (that's the highest point) and then plug this t into your y equation. 55 / 32 = 1.72 seconds. Substituting into the y equation, max height is 81.27 ft.
2007-02-22 00:30:59 · answer #1 · answered by Jamestheflame 4 · 0⤊ 0⤋