a linerbacker starts from rest and accelerates at a constant rate for 2.0 s to make a tackle 7.0 m away ,?

Question

what was the acceleration and the speed when making the tackle?

Answer 1

x = 1/2at^2
7 = 1/2(a)(2)^2
14 = 4a
a = 3.5m/s^2

Answer 2

s = 1/2 at^2, where s = 7 m and t = 2 sec.

Thus, a = 2s/t^2 (You can do the math).

Lesson learned: There is a set of equations involving distance (S), time (T), acceleration (A), and velocity (U and V). They are called the SUVAT equations. You should learn them well because they show up in physics exams all the time.

Answer 3

v= d/t

a=delta v/delta t

v= 3.5 (speed)

a= 1.75 (acceleration)

This COULD be wrong, as I am a bit rusty, but if memory serves, these formulas are correct.