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Does the acceleration of a freely falling object depend to any extent on the location, -- that is, whether the object is on top of Mt. Everest or in Death Valley, California?

2007-02-21 10:28:48 · 7 answers · asked by Esther 1 in Science & Mathematics Physics

7 answers

In actuality yes but under almost every case the difference is negligible since the distance that matters is the distance between the object and the earth center and this distance is much larger than the respective altitude difference. 9.81 m/s^2 and 32.2 ft/s^2 will most always be used.

2007-02-21 10:34:20 · answer #1 · answered by Michael 2 · 1 0

Excellent question...in fact it does.

We often use something like g = 9.81 m/sec^2 or 32.2 ft/sec^2 in physics problems to represent the average acceleration due to gravity AT EARTH's surface. This g value, however, is strongly dependent on the mass of the Earth (M), mass of the falling object (m), and the square of the distances (r^2) between the centers of the two masses.

If g(r = R) is the gravitational acceleration at Earth's surface (or any planetary surface) and g(r = R + h) is the gravitation acceleration at altitude h above that surface, we can write g(r = R + h) = g(r = R)(R^2)/(R + h)^2. Thus, as you can see, the acceleration of a freely falling body at altitude would be less than that same body on the surface.

2007-02-21 10:43:24 · answer #2 · answered by oldprof 7 · 0 0

relies upon the place you're. At sea point that's 9.81m/s^2. The Newtonian regulation is: a = GM/r^2 the place M is the mass of the physique you're falling in the direction of, and r is the gap to its centre. So for our bodies of the comparable density d=M/R^3, this suggests that a=GRd, that's why the acceleration by means of gravity is lots extra suitable on the earth than on the Moon.

2016-12-18 08:14:30 · answer #3 · answered by ? 4 · 0 0

well, the acceleration of gravity is generically said to be 9.8 meters/second squared. It will probably differ at those two locations since they are at extreme elevations on earth. The air pressure at the top of Mt. Everest would be very different than at sealevel, ditto for Death Valley. And air pressure interferes with acceleration, but it most likely can't be measured though

2007-02-21 10:34:08 · answer #4 · answered by Mikey 2 · 0 2

To Any Extent

2016-11-06 22:15:54 · answer #5 · answered by leinen 4 · 0 0

Yes. The acceleration due to gravity varies depending on the distance from the center of the Earth and the density of the underlying local rocks.

You can buy meters to measure local gravity, and oil companies use these to look for oil.

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If the mission meets all of its goals, the knowledge of the gravitational field will be improved by a factor of well over 100, and changes in the field will be determined on a monthly basis. The improvement in the static (time-independent) gravity field will effectively eliminate the uncertainty in the height of the equipotential reference surface (referred to as the "geoid"), which is the largest error source for existing ocean altimetry missions such as TOPEX/Poseidon and Jason-1.

Beyond the static field, the time-varying gravity measurements have a huge potential to constrain mass motions in the ocean, cryosphere, and hydrosphere that are important to understanding the Earth's climate. Ultimately, the powerful combination of altimetry data over the ocean and ice sheets (for example from ICESat) and the time-varying gravity information from GRACE will have enormous impact on our understanding of climate change on Earth. ...

2007-02-21 10:33:22 · answer #6 · answered by Randy G 7 · 0 0

The denser the air (barometric pressure I believe relates to it) the slower an object will accelerate. Wind speed and direction also will effect this.

2007-02-21 10:38:39 · answer #7 · answered by carpentryman05 2 · 0 2

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