The question is about "Parallel and Perpendicular Lines":
The question is: Through (3,-2) parallel to 2x-y=5
This IS my homework and I need a formula or something, so please tell me a website, or work this one out for me so I can do the rest myself. (Thankz soooo much)
2007-02-21 10:13:46 · 3 answers · asked by B-Rad 4 in Education & Reference ➔ Homework Help
The start question is:
"Write equations in standard form for each of the following lines"
2007-02-21 10:29:50 · update #1
if it is parallel, it will have the same slope. So you put the 2x-y=5 into y=mx+b form. so it would be: y= 2x-5 Then, you put the point (3,-2) on the graph. from there, you would go up 2, then to the right 1. (on the graph) Hope I helped! I'm really good at math, so if you ahve any more questions message me! =]
2007-02-21 10:19:57 · answer #1 · answered by Allie =] 2 · 0⤊ 0⤋
i guess it will be like this:
2x - y = 5
-y = 5 - 2x
y = - (5 - 2x)
y = -5 + 2x
y = 2x - 5
y = mx + c
m = 2, c = -5
x = 3, y = -2
y = mx + c
-2 = 2(3) + c
-2 = 6 + c
6 + c = -2
c = -2 - 6
c = -8
Answer : y = 2x - 8
or also can be:
y = 2x - 8
2x - 8 = y
2x - y = 8
i guess.. but not so sure..
2007-02-21 18:47:52 · answer #2 · answered by hate_the_lights 1 · 0⤊ 0⤋
look for math on call and there should be a 1800 # that will be able to help you
2007-02-21 18:16:26 · answer #3 · answered by angelbaby8087 2 · 0⤊ 0⤋