2007-02-21 07:47:10 · 10 answers · asked by Anonymous in Entertainment & Music ➔ Music
If they make each other happy which it appears they do then I think they make the perfect couple.
2007-02-21 07:55:26 · answer #1 · answered by JELLE 3 · 1⤊ 0⤋
I think they make a good couple in "their own way" simply because they are both rich.....Beyonce is cute and JayZ is ugly so she'll never really have to worry about anyone trying to steal him from her which is why I think she chose him......they have a "Beauty and the Beast" storyline.
2007-02-21 08:03:05 · answer #2 · answered by free_spirit5230 2 · 1⤊ 0⤋
Definitely Angelina&Brad.
2016-05-24 03:50:06 · answer #3 · answered by Anonymous · 0⤊ 0⤋
No way. Jay-Z could do so much better than her. I really dont like her, I dont think she is as pretty as everyone makes her out to be, I have heard female vocalists much better than her. And in interviews she is just so dense. No, he could find someone much better than her.
2007-02-21 07:52:36 · answer #4 · answered by Henry ♫ 5 · 1⤊ 0⤋
I believe that they make a wonderful Hollywood couple! However, if neither one were superstars they would be a mismatch!
2007-02-21 07:51:51 · answer #5 · answered by ncbratonia 2 · 0⤊ 0⤋
yea'.he ugly but cute in a rapper sort of way and she pretty and look stuck up
2007-02-21 08:42:18 · answer #6 · answered by Anonymous · 1⤊ 0⤋
absolutely not. Beyonce is an idiot.
2007-02-21 07:50:46 · answer #7 · answered by Neil T 1 · 1⤊ 0⤋
nope she deserves some1 better
2007-02-22 04:05:29 · answer #8 · answered by Frihah Anti-Milanist 4lyf! 6 · 0⤊ 0⤋
not at all!, I should'nt say anything else.
2007-02-21 07:57:13 · answer #9 · answered by Dane Cruz 5 · 1⤊ 0⤋
yeah they really do.....................................................................................................................................................................................................................................................................................
2007-02-21 07:54:38 · answer #10 · answered by yung_blood 2 · 0⤊ 0⤋