If a 10kg mass is dropped from a height of 2 meters (free fall for this distance) and then rapidly decelerates to a stop in just 1cm distance. What is the average deceleration force on the mass?
2007-02-21 07:42:12 · 2 answers · asked by GSU 1 in Science & Mathematics ➔ Physics
Aaaaahh! Physics, I hate Physics! Don't ask any more questions on Physics!! I am now a nervous wreck!! Thanx
2007-02-21 07:50:29 · answer #1 · answered by melina 2 · 0⤊ 0⤋
free fall for 2 m implies velocity after falling thru 2m is square root of 2g(2) ...that is initial velocity =40 (taking g=10m/s)
let decelaration be a then Newton's equation implies
v^2 = u^2 - 2as
- sign coz decelration and s is distance covered dring which velocity changed from u to v.
since v = 0 as body stops finally.
0 = 40 -2a (.001)
-40 /.002 = a
a= 2000 m/s
2007-02-21 16:01:48 · answer #2 · answered by Curious23 1 · 0⤊ 0⤋