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given the previous information that the speed of sound is 330m/s and the speed of light is 3x10 (little)8 m/s and the previous question tells us to work out the frequency using 100mm as wavelength using the formula wavespeed = frequency x wavelength

2007-02-21 06:16:48 · 7 answers · asked by Anonymous in Science & Mathematics Physics

7 answers

Distance covered, S is the product of velocity, V and time, T i.e
D = VT so
D = 330 x 1.5
= 495m/s
the speed of light is negligible as compared to sound so the lightning is about four hundred and ninty five meters away from the observer.

2007-02-21 07:34:50 · answer #1 · answered by bitrus d 1 · 1 0

provided that easy travels at a critically better speed than sound by using air, an observer can approximate the area to the strike via timing the era between the seen lightning and the audible thunder it generates. At general atmospheric temperature and pressures close to floor point, sound will commute at extra or less 343 m/s (1125 ft/sec); a lightning flash previous its thunder via 5 seconds could be approximately one mile distant. A flash previous thunder via 3 seconds is approximately one kilometer distant.

2016-12-17 15:28:49 · answer #2 · answered by hirschfeld 4 · 0 0

Wait one sec. Not all bolts of lightning strike the ground or areas conducive to a calculation. Only speculation of a strike within the parameters of 360 degrees from a central point gives an estimated answer.

2007-02-21 06:31:02 · answer #3 · answered by Coyote 2 · 0 0

330m/s for 1.5 sec. = 495 metres away.

0.495 km = 587 yards

2007-02-21 07:59:12 · answer #4 · answered by Norrie 7 · 0 0

About half a kilometre.

2007-02-21 06:20:08 · answer #5 · answered by Leviathan 6 · 0 0

495 meters away.

2007-02-21 06:23:41 · answer #6 · answered by Anthony Stark 5 · 0 0

'bout 3.5 miles

2007-02-21 06:24:51 · answer #7 · answered by ? 6 · 0 0

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