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A steel ball of mass 1.41 kg is attached to a thin (massless) cable and whirled around in a circle in a vertical plane.The circle has a radius of 1.58 m. When it is at the bottom of the circle, the ball has a speed of 12.3 m/s. Calculate the magnitude of the tension in the cable when the mass is at the bottom of the circle.

2007-02-21 03:36:32 · 1 answers · asked by Anonymous in Science & Mathematics Physics

1 answers

T=W+Fc
W=mg (weight)
Fc = m ac (centripital force)
ac = v^2/R centripital acceleration

v- velocity
R - radius

Fc= m V^2/R
finally

T=mg + m V^2/R =m(g + V^2/R)
T=1.41(9.81 + (12.3 )^2/1.58)
T=149 N

2007-02-21 06:16:20 · answer #1 · answered by Edward 7 · 0 0

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