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Man, running at 4.427 m/s, while carrying a 1 kg mass 1 m off the ground.
Pot. en. = m*g*h = 9.8 J

KE = 1/2 * m * v^2 = 9.8 J

2007-02-21 10:32:26 · answer #1 · answered by sojsail 7 · 0 0

Most objects constantly trade potential for kinetic energy.

I'm not sure about this- but would an Object in orbit of the earth have an equivalent kinetic and potential energy? Perhaps at a specific altitude of orbit?

2007-02-21 04:05:19 · answer #2 · answered by Morey000 7 · 0 0

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