hi there, i am trying to write a program for my uni comp module on poker odds and i am having dificulity finding the algorithm for the odds of a hand wining pre and post frop, please if any of you would know the mathmatical algorithm(s) for this please let me know or link me to as site or someting that may have the answer as i am at a loss to find it so far! many thanks, Chris :)
2007-02-20 23:34:52 · 3 answers · asked by Christopher 2 in Science & Mathematics ➔ Mathematics
Winning against what? I mean if I have AK, do you want the odds vs AQ, 27, or what? Against 1 player, or against several?
I think lots of programs do this by simulating thousands of possible hands and taking the overall percentage- it's easier than storing a table of 52x52hands vs 51x50 other possible hands.
2007-02-22 08:54:00 · answer #1 · answered by Sean M 1 · 0⤊ 0⤋
Why do you get "fed" up with these guys? You just wait for a hand and a good opportunity to bust them. A5 and A3 are not necessarily the hands to do it with although it depends a lot on stack sizes and how many players are left to act after you. Against a completed random hand A5o only wins about 58% of the time meaning if the maniac shoved with any 2 cards he would still win around 42% of the time. If he's only shoving a third of the top hands in the deck his hand is actually a favorite to beat yours around 54% of the time. This doesn't even take into account opponents who wake up with huge hands behind you. Final point, it's just one tournament. Even if you did everything right you're not going to win or even make the money very often in a typical online tournament. The player field is large and usually only the top 10% or so win money.
2016-03-29 05:28:31 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Guess you are just too lazy to type "Poker Probability" into Yahoo search.
So I've done it for you and got dozens of hits on the first page - here's 3 of them ...
If you don't understand any of them, try attending Maths Class next time they cover Probability Theory.
2007-02-23 09:47:13 · answer #3 · answered by Steve B 7 · 0⤊ 0⤋