Algebra problem!!!!!!?

4 ⤊

Algebra problem!!!!!!?

Can someone teach me how to do the procedure of "law of negative exponet" like : (x/y) exponent n. how is the procedure???? is there any website out there????

2007-02-20 23:27:43 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

3 answers

(x/y) ^ n = x^n / y^n

or x^n(y^(-n)

for example

(1/2) ^3 = 1^3/2^3= 1/8

or 1^3 * 2^(-3) = 1/8

2007-02-20 23:35:41 · answer #1 · answered by Mein Hoon Na 7 · 1⤊ 0⤋

a^-b = 1/a^b so 2^-5=1/2^5 .Nothing further

2007-02-21 07:36:11 · answer #2 · answered by santmann2002 7 · 1⤊ 0⤋

For n = positive

(x/y)^(-n)
=(y/x)^n

Just simply reverse the numerator and denominator.

2007-02-21 07:36:07 · answer #3 · answered by Bored 3 · 2⤊ 0⤋