2007-02-20 23:13:41 · 10 answers · asked by angel 1 in Science & Mathematics ➔ Mathematics
490/560
Divide numerator and denominator by 10:
=49/56
Both numerator and denominator are divisible by 7 also:
=7/8
Hope that helps ;)
2007-02-20 23:17:09 · answer #1 · answered by MamaMia © 7 · 1⤊ 0⤋
Reduce completely 490/560
The common factor for the numerator and denominator is 70
490 divided by 70 = 7
560 divided by 70 = 8
490/560 = 7/8
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2007-02-20 23:55:34 · answer #2 · answered by SAMUEL D 7 · 0⤊ 0⤋
dropping the 0's make this easier to do
490/560=49/56 divide by 7/7 =7/8
2007-02-21 02:30:22 · answer #3 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋
The easiest way to do this is throw away the 0's (i.e. divide by 10). This will give you 49/56. Now, divide each number by 7 to get 7/8.
2007-02-20 23:18:20 · answer #4 · answered by Anonymous · 0⤊ 0⤋
7/8. Divide numerator and denominator by 70.
2007-02-20 23:18:04 · answer #5 · answered by Anonymous · 0⤊ 0⤋
49/56 = 7/8
2007-02-20 23:18:05 · answer #6 · answered by thomasrobinsonantonio 7 · 0⤊ 0⤋
Divide the top and bottom by 70.
2007-02-20 23:17:31 · answer #7 · answered by Curt Monash 7 · 0⤊ 0⤋
84
2007-02-20 23:15:42 · answer #8 · answered by john y 3 · 0⤊ 2⤋
Plug it into the y=mx+b formula
crunch the numbers and end up with OU812
2007-02-20 23:23:09 · answer #9 · answered by Anonymous · 0⤊ 0⤋
7/8 or .875
2007-02-20 23:21:02 · answer #10 · answered by mrjomorisin 4 · 0⤊ 0⤋