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I want to know, for example, C6H6. It is benzene. But if I want to know C7H9, C6H7O, etc. where to look for?

2007-02-20 21:48:51 · 3 answers · asked by asridar a 1 in Science & Mathematics Chemistry

3 answers

Try this http://www.chemindustry.com/apps/chemicals

if you have commercial purposes, but I should warn you that you may not get all the stuff there

2007-02-20 23:35:27 · answer #1 · answered by <B-NOY><% 2 · 0 0

you have to use the IUPAC rules !

The International Union of Pure and Applied Chemistry (IUPAC) (Pronounced as "eye-you-pack") is an international non-governmental organization established in 1919 devoted to the advancement of chemistry. It has as its members national chemistry societies. It is most well known as the recognized authority in developing standards for the naming of the chemical elements and their compounds, through its Interdivisional Committee on Nomenclature and Symbols (IUPAC nomenclature). It is a member of the International Council for Science (ICSU).

In addition to nomenclature guidelines, the IUPAC sets standards for international spelling in the event of a dispute; for example, it ruled that British aluminium is preferable to the American aluminum and American sulfur is preferable to the British sulphur.

Many IUPAC publications are available over the Internet. For example, the Green Book ("Quantities, Units and Symbols in Physical Chemistry, 2nd edition, 1993") can be downloaded in its entirety from

http://www.iupac.org/publications/books/gbook/green_book_2ed.pdf.

The 2005 version (a work-in-progress) can also be downloaded.

I personally love this website:
http://www.chem.qmul.ac.uk/iupac/
very complete and very easy to understand.

another one very complete
http://www.acdlabs.com/iupac/nomenclature/

2007-02-20 23:40:09 · answer #2 · answered by scientific_boy3434 5 · 0 1

The best resource for this is the Merck Index. Sadly, it's not free.

You can try ChemFinder which is free. http://chemfinder.cambridgesoft.com/

2007-02-20 21:53:59 · answer #3 · answered by ashwan_lewis 2 · 0 0

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