I'm trying to study for a Calc test tomorrow but i'm really having problem understanding one part of this problem. I already came up with the right aswer, but only b/c the multiple choice questions kinda gave it away, I really need help plz
Evaluate the integral:
integral [ x/(81+x^4)] dx
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Here is where the problem starts...i know that i have to let 'x' equal to something, but I dont know how to do that. Once again, the only reason why I was able to get tthe right answer was by looking at the multiple choice answers and figuring it out from there...
x= sqrt(tan 9t) { this implies that t= arctan (x^2)/9 }
dx= (9sec^2 9t)*[1/2 (tan 9t)^(-1/2)] dt
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thus....
integral [ x/ (81+x^4)] dx=
integral [ sqrt(tan 9t)/ (81-(tan 9t)^2 )] * [1/ 2sqrt(tan9t)]* 9sec^2 (9t)
And if simplify you get
(1/18)arctan [(x^2)/9] + C
2007-02-20
19:28:03
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4 answers
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asked by
Sir Excalibur
2
in
Science & Mathematics
➔ Mathematics
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NORTHSTAR if you are still on here, when you do the following...
Integrate ∫[x/(81+x^4)]dx.
Let
9tanθ = x²
9sec²θdθ = 2xdx
(9/2)sec²θdθ = xdx
how do you know to let ' 9tanθ = x² ', this is what im having problems with
2007-02-20
19:53:12 ·
update #1